CLEP College Algebra Practice Test

10 free sample questions with answers and explanations. See how you'd score on the real CLEP exam.

Question 1Unit 1: Algebraic Foundations

Which of the following is equivalent to (2^3)^2?

A
A) 2^6
B
B) 2^5
C
C) 2^8
D
D) 2^9
E
E) 2^12

Explanation

To find the equivalent expression, we apply the power of a power rule, which states that (a^m)^n = a^(m*n). In this case, (2^3)^2 = 2^(3*2) = 2^6. This rule is a fundamental property of exponents, allowing us to simplify expressions with multiple layers of exponents. The correct answer, 2^6, demonstrates the application of this rule. The distractors are incorrect because they do not apply the power of a power rule correctly: option "2^6" incorrectly adds the exponents, option "2^8" raises 2 to the power of the product of 3 and 3, option "2^9" raises 2 to the power of the product of 3 and 3 plus 1, and option "2^12" raises 2 to the power of the product of 3 and 4.

Question 2Unit 1: Algebraic Foundations

What is (2x - 3y)^2?

A
A) 4x^2 - 12xy + 9y^2
B
B) 12xy - 9y^2
C
C) 4x^2 + 12xy + 9y^2
D
D) 4x^2 - 9y^2
E
E) 4x^2 - 9y^2 - 12xy

Explanation

4x^2 - 12xy + 9y^2 is correct because the binomial theorem states that (a - b)^2 = a^2 - 2ab + b^2, so (2x - 3y)^2 = (2x)^2 - 2*(2x)*(3y) + (3y)^2 = 4x^2 - 12xy + 9y^2.

Question 3Unit 1: Algebraic Foundations

What is the constant term of the expansion of (x + 1/x)^4?

A
A) 0
B
B) 2
C
C) 3
D
D) 4
E
E) 6

Explanation

6 is correct because the constant term of (x + 1/x)^4 occurs when two terms contribute x and the other two contribute 1/x, so the constant term is [4!/(2!(4-2)!)] = 6.

Question 4Unit 1: Algebraic Foundations

What is the 3rd term in the expansion of (x + 2)^5?

A
A) 10x^3
B
B) 40x^2
C
C) 20x^4
D
D) 10x^2
E
E) 40x^3

Explanation

40x^3 is correct because the binomial theorem states that the kth term of (a + b)^n is [n!/(k!(n-k)!)]*a^(n-k)*b^k, and for the 3rd term of (x + 2)^5, k = 2, so the term is [5!/(2!(5-2)!)]*x^(5-2)*2^2 = 40x^3.

Question 5Unit 1: Algebraic Foundations

What is the formula for the nth term of the sequence 1, 4, 9, 16, 25?

A
A) an = n
B
B) an = 2n
C
C) an = n³
D
D) an = n²
E
E) an = 2n + 1

Explanation

n² is correct because the sequence is obtained by squaring the term number, so the nth term is n².

Question 6Unit 1: Algebraic Foundations

What is the sum of the first 5 terms of the sequence 2, 4, 6, 8, 10?

A
A) 20
B
B) 30
C
C) 40
D
D) 50
E
E) 60

Explanation

30 is correct because the sum of an arithmetic series can be found by averaging the first and last terms and multiplying by the number of terms, so (2+10)/2 * 5 = 30.

Question 7Unit 1: Algebraic Foundations

Solve the inequality: x > 3 + 2x

A
A) x > -3
B
B) x < -3
C
C) x < 3
D
D) x > 3
E
E) x < 1

Explanation

x < -3 is correct because subtracting 2x from both sides of x > 3 + 2x gives -x > 3, and then multiplying by -1 and reversing the inequality gives x < -3, applying the rules of solving linear inequalities.

Question 8Unit 1: Algebraic Foundations

Solve for x: x/4 = 9

A
A) 2
B
B) 4
C
C) 9
D
D) 36
E
E) 45

Explanation

36 is correct because multiplying both sides of x/4 = 9 by 4 gives x = 36, applying the rule of solving linear equations.

Question 9Unit 1: Algebraic Foundations

What is the inverse of the function f(x) = e^x?

A
A) f^{-1}(x) = ln(x)
B
B) f^{-1}(x) = e^x
C
C) f^{-1}(x) = x - 1
D
D) f^{-1}(x) = x^2
E
E) f^{-1}(x) = 1/x

Explanation

ln(x) is correct because the inverse of the exponential function e^x is the natural logarithm function ln(x), since e^(ln(x)) = x and ln(e^x) = x.

Question 10Unit 1: Algebraic Foundations

If f(x) = 2x + 1 and g(x) = (x-1)/2, are f and g inverse functions?

A
A) yes, since f(g(x)) = x
B
B) yes, since g(f(x)) = x
C
C) no, since f(g(x)) != x
D
D) no, since g(f(x)) != x
E
E) yes, since f(g(x)) = g(f(x)) = x

Explanation

Inverse functions satisfy the condition that their composition equals the input, meaning f(g(x)) = x and g(f(x)) = x. Since f(g(x)) and g(f(x)) both simplify to x, f and g are indeed inverse functions.

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